Stiff Clay with Free Water (Reese)[Reese et al., 1975]

Static Loading Condition

Figure 1. p − y curve for static loading in stiff clay with free water[Reese and Van Impe, 2011]

Obtain undrained shear strength cuc_u, soil submerged unit weight γγ′ and compute the average undrained shear strength cac_a over the depth zz and value of cuc_u at depth zz.

pup_u, the ultimate soil resistance per unit length of pile defined as:

pu=min(pct,pcd)(1)\tag{1} p_u = min(p_{ct},{p_cd})
pct=2cab+γbz+2.83caz(2)\tag{2} p_{ct} = 2c_ab+\gamma'bz+2.83c_az
pcd=11cub(3)\tag{3} p_{cd} = 11c_ub

Initial straight-line portion of the p-y curve,

p=(kpyz)y(4)\tag{4} p = (k_{py}z)y

Following values are suggested for kpyk_{py} over-consolidated clay by [Reese and Van Impe, 2011],

ca(kPA)c_a(kPA)

5010050-100

100200100-200

300400300-400

kpy (static)(MN/m3)

135

270

540

kpy (cyclic)(MN/m3)

55

110

540

Define y50y_{50} as,

y50=ε50b(5)\tag{5} y_{50} = \varepsilon_{50}b

Following values are suggested for ε50ε_{50} over-consolidated clay by [Reese and Van Impe, 2011].

ca(kPA)ca(kPA)

5010050-100

100200100-200

300400300-400

ε50ε_{50}

0.007

0.005

0.004

Obtaion As from following figure,

Figure 2. Constants for As and Ac [Reese and Van Impe, 2011]

First parabolic portion of the p-y curve is given by the Eqn. (6). This portion extends from yy is equal to intersection of Eqn. (4) and Eqn. (6) to yy is equal to Asy50A_sy_{50}.

p=0.5pu(yy50)0.5(6)\tag{6} p = 0.5p_u(\frac{y}{y_{50}})^{0.5}

Second parabolic portion of the p-y curve is given by the Eqn. (7). This portion extends from yy is equal to Asy50A_sy_{50} to yy is equal to 6Asy506A_sy_{50}.

p=0.5pu(yy50)0.50.055pu(yAsy50Asy50)1.25(7)\tag{7} p = 0.5p_u(\frac{y}{y_{50}})^{0.5} - 0.055p_u(\frac{y-A_sy_{50}}{A_sy_{50}})^{1.25}

Next straight line portion of the p-y curve is given by the Eqn. (8). This portion extends from yy is equal to 6Asy506A_sy_{50} to yy is equal to 18Asy5018A_sy_{50}.

p=0.5pu(6As)0.50.411pu0.0625y50pu(y6Asy50)(8)\tag{8} p = 0.5p_u(6A_s)^{0.5}-0.411p_u-\frac{0.0625}{y_{50}}p_u(y-6A_sy_{50})

Establish the final straight-line portion of the p-y curve,

p=0.5pu(6As)0.50.411pu0.75puAs(9)\tag{9} p = 0.5p_u(6A_s)^{0.5}-0.411p_u-0.75p_uA_s \quad

or

p=pu(1.225As0.750.411)(10)\tag{10} p= p_u (1.225\sqrt{A_s}-0.75-0.411)

[Reese and Van Impe, 2011] states that there might be no intersection between Eqn. (6) with any of the other equations given to define portions of the p-y curve. Eqn. (6) defines the p-y curve until it intersects with one of the other equations. However, if no intersection occurs, the p-y curve is defined by Eqn. (6).

Cyclic Loading Condition

Straight portion of the curve is same as static loading condition.

Choose appropriate value for AcA_c from the Figure 2. and compute the following value:

yp=4.1Acy50(11)\tag{11} y_p = 4.1A_cy_{50}

First parabolic portion of the p-y curve is given by the Eqn. (12). This portion extends from yy is equal to intersection of Eqn. (4) and Eqn. (12) to yy is equal to 0.6yp0.6yp.

p=Acpu[1y0.45yp0.45yp0.25](12)\tag{12} p = A_cp_u\Bigg[1- \Bigg|\frac{y-0.45y_p}{0.45y_p}\Bigg|^{0.25}\Bigg]

The next straight portion of the p-y curve is given by the Eqn. (13). This straight line lies in between from yy is equal to 0.6yp0.6yp to yy is equal to 1.8yp1.8yp.

p=0.936Acpu0.085y50pu(y0.6yp)(13)\tag{13} p = 0.936A_cp_u-\frac{0.085}{y_{50}}p_u(y-0.6y_p)

Lastly, final straight portion of the curve is given by the following,

p=0.936Acpu0.102y50puyp(14)\tag{14} p = 0.936A_cp_u-\frac{0.102}{y_{50}}p_uy_p

[Reese and Van Impe, 2011] states that there might be no intersection between Eqn. (12) with any of the other equations given to define portions of the p-y curve. Eqn. (12) defines the p-y curve until it intersects with one of the other equations. However, if there is no intersection occurs, p-y curve is defined by smallest value of pp for any value of yy.

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